9^(x+2)=2(4x-5)

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Solution for 9^(x+2)=2(4x-5) equation: 



9^(x+2)=2(4x-5)

We move all terms to the left:

9^(x+2)-(2(4x-5))=0



We calculate terms in parentheses: -(2(4x-5)), so:

2(4x-5)

We multiply parentheses

8x-10

Back to the equation:

-(8x-10)



We get rid of parentheses

9^(x+2)-8x+10=0

We add all the numbers together, and all the variables

-8x+9^(x+2)+10=0

We move all terms containing x to the left, all other terms to the right

-8x+9^(x+2)=-10

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